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101433440201 = 175966672953
BaseRepresentation
bin101111001110111100…
…1110111011111001001
3100200211001220122112112
41132131321313133021
53130213430041301
6114333050352105
710220421005312
oct1363571673711
9320731818475
10101433440201
113a021594a25
12177a9a2b635
139746799002
144ca3599609
152989ed79bb
hex179de777c9

101433440201 has 4 divisors (see below), whose sum is σ = 107400113172. Its totient is φ = 95466767232.

The previous prime is 101433440189. The next prime is 101433440219. The reversal of 101433440201 is 102044334101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 94418540176 + 7014900025 = 307276^2 + 83755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101433440201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (101433440231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2983336460 + ... + 2983336493.

It is an arithmetic number, because the mean of its divisors is an integer number (26850028293).

Almost surely, 2101433440201 is an apocalyptic number.

It is an amenable number.

101433440201 is a deficient number, since it is larger than the sum of its proper divisors (5966672971).

101433440201 is an equidigital number, since it uses as much as digits as its factorization.

101433440201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5966672970.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 101433440201 its reverse (102044334101), we get a palindrome (203477774302).

The spelling of 101433440201 in words is "one hundred one billion, four hundred thirty-three million, four hundred forty thousand, two hundred one".

Divisors: 1 17 5966672953 101433440201