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10144422131 = 33130647801
BaseRepresentation
bin10010111001010011…
…11001100011110011
3222011222112001001012
421130221321203303
5131233433002011
64354342101135
7506250110504
oct113451714363
928158461035
1010144422131
114336297548
121b7141a7ab
13c588b555c
146c33d8bab
153e58d9a8b
hex25ca798f3

10144422131 has 4 divisors (see below), whose sum is σ = 10175070264. Its totient is φ = 10113774000.

The previous prime is 10144422109. The next prime is 10144422157. The reversal of 10144422131 is 13122444101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10144422131 - 222 = 10140227827 is a prime.

It is a super-2 number, since 2×101444221312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10144422097 and 10144422106.

It is not an unprimeable number, because it can be changed into a prime (10144422161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15323570 + ... + 15324231.

It is an arithmetic number, because the mean of its divisors is an integer number (2543767566).

Almost surely, 210144422131 is an apocalyptic number.

10144422131 is a deficient number, since it is larger than the sum of its proper divisors (30648133).

10144422131 is an equidigital number, since it uses as much as digits as its factorization.

10144422131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30648132.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 10144422131 its reverse (13122444101), we get a palindrome (23266866232).

The spelling of 10144422131 in words is "ten billion, one hundred forty-four million, four hundred twenty-two thousand, one hundred thirty-one".

Divisors: 1 331 30647801 10144422131