Base | Representation |
---|---|
bin | 1001001110101011001011… |
… | …1101000101110010110011 |
3 | 1022221010000201021102202201 |
4 | 2103222302331011302303 |
5 | 2312230010032041430 |
6 | 33325443532324031 |
7 | 2065101561154660 |
oct | 223526275056263 |
9 | 38833021242681 |
10 | 10147715112115 |
11 | 32626926a3079 |
12 | 117a841313617 |
13 | 587c052241c9 |
14 | 27121b266a67 |
15 | 128e731388ca |
hex | 93ab2f45cb3 |
10147715112115 has 16 divisors (see below), whose sum is σ = 13921550818560. Its totient is φ = 6956091030240.
The previous prime is 10147715112107. The next prime is 10147715112169. The reversal of 10147715112115 is 51121151774101.
It is not a de Polignac number, because 10147715112115 - 23 = 10147715112107 is a prime.
It is a super-2 number, since 2×101477151121152 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48690145 + ... + 48898114.
It is an arithmetic number, because the mean of its divisors is an integer number (870096926160).
Almost surely, 210147715112115 is an apocalyptic number.
10147715112115 is a deficient number, since it is larger than the sum of its proper divisors (3773835706445).
10147715112115 is an equidigital number, since it uses as much as digits as its factorization.
10147715112115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97591242.
The product of its (nonzero) digits is 9800, while the sum is 37.
Adding to 10147715112115 its reverse (51121151774101), we get a palindrome (61268866886216).
The spelling of 10147715112115 in words is "ten trillion, one hundred forty-seven billion, seven hundred fifteen million, one hundred twelve thousand, one hundred fifteen".
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