Base | Representation |
---|---|
bin | 10010111010100101… |
… | …10001111011110011 |
3 | 222012201200111112222 |
4 | 21131102301323303 |
5 | 131244203420203 |
6 | 4355403511255 |
7 | 506440153445 |
oct | 113522617363 |
9 | 28181614488 |
10 | 10155138803 |
11 | 43413470a7 |
12 | 1b74b2852b |
13 | c5ab98394 |
14 | 6c49c8495 |
15 | 3e6805038 |
hex | 25d4b1ef3 |
10155138803 has 4 divisors (see below), whose sum is σ = 10155563880. Its totient is φ = 10154713728.
The previous prime is 10155138793. The next prime is 10155138809. The reversal of 10155138803 is 30883155101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30883155101 = 1063 ⋅29052827.
It is a cyclic number.
It is not a de Polignac number, because 10155138803 - 210 = 10155137779 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10155138809) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174425 + ... + 225242.
It is an arithmetic number, because the mean of its divisors is an integer number (2538890970).
Almost surely, 210155138803 is an apocalyptic number.
10155138803 is a deficient number, since it is larger than the sum of its proper divisors (425077).
10155138803 is an equidigital number, since it uses as much as digits as its factorization.
10155138803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425076.
The product of its (nonzero) digits is 14400, while the sum is 35.
The spelling of 10155138803 in words is "ten billion, one hundred fifty-five million, one hundred thirty-eight thousand, eight hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •