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10160143313 = 17670189189
BaseRepresentation
bin10010111011001011…
…10111101111010001
3222020002002202110012
421131211313233101
5131301444041223
64400103044305
7506530536035
oct113545675721
928202082405
1010160143313
114344155061
121b76740695
13c5bc2b228
146c552c1c5
153e6e92c78
hex25d977bd1

10160143313 has 8 divisors (see below), whose sum is σ = 10759524840. Its totient is φ = 9560953600.

The previous prime is 10160143309. The next prime is 10160143327. The reversal of 10160143313 is 31334106101.

It can be written as a sum of positive squares in 4 ways, for example, as 661106944 + 9499036369 = 25712^2 + 97463^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10160143313 - 22 = 10160143309 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10160143813) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69323 + ... + 158511.

It is an arithmetic number, because the mean of its divisors is an integer number (1344940605).

Almost surely, 210160143313 is an apocalyptic number.

It is an amenable number.

10160143313 is a deficient number, since it is larger than the sum of its proper divisors (599381527).

10160143313 is an equidigital number, since it uses as much as digits as its factorization.

10160143313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95907.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 10160143313 its reverse (31334106101), we get a palindrome (41494249414).

The spelling of 10160143313 in words is "ten billion, one hundred sixty million, one hundred forty-three thousand, three hundred thirteen".

Divisors: 1 17 6701 89189 113917 1516213 597655489 10160143313