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10200100313003 = 67489151137227
BaseRepresentation
bin1001010001101110010101…
…0110110001011110101011
31100010010020112021100220012
42110123211112301132223
52314104301140004003
633405510021122135
72101634665056116
oct224334526613653
940103215240805
1010200100313003
11328292478a927
121188a20b5934b
1358cb3319a7b3
1427398a68357d
1512a4dc0ce8d8
hex946e55b17ab

10200100313003 has 4 divisors (see below), whose sum is σ = 10200251517720. Its totient is φ = 10199949108288.

The previous prime is 10200100312999. The next prime is 10200100313009. The reversal of 10200100313003 is 30031300100201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10200100313003 - 22 = 10200100312999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10200100313009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75501125 + ... + 75636102.

It is an arithmetic number, because the mean of its divisors is an integer number (2550062879430).

Almost surely, 210200100313003 is an apocalyptic number.

10200100313003 is a deficient number, since it is larger than the sum of its proper divisors (151204717).

10200100313003 is an equidigital number, since it uses as much as digits as its factorization.

10200100313003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151204716.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10200100313003 its reverse (30031300100201), we get a palindrome (40231400413204).

The spelling of 10200100313003 in words is "ten trillion, two hundred billion, one hundred million, three hundred thirteen thousand, three".

Divisors: 1 67489 151137227 10200100313003