1020433431131 has 4 divisors (see below), whose sum is σ = 1021629719712. Its totient is φ = 1019237142552.

The previous prime is 1020433431089. The next prime is 1020433431209. The reversal of 1020433431131 is 1311343340201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1020433431131 is a prime.

It is a super-2 number, since 2×1020433431131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1020433431131.

It is not an unprimeable number, because it can be changed into a prime (1020433439131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598143011 + ... + 598144716.

It is an arithmetic number, because the mean of its divisors is an integer number (255407429928).

Almost surely, 2^{1020433431131} is an apocalyptic number.

1020433431131 is a deficient number, since it is larger than the sum of its proper divisors (1196288581).

1020433431131 is an equidigital number, since it uses as much as digits as its factorization.

1020433431131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1196288580.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1020433431131 its reverse (1311343340201), we get a palindrome (2331776771332).

The spelling of 1020433431131 in words is "one trillion, twenty billion, four hundred thirty-three million, four hundred thirty-one thousand, one hundred thirty-one".