10210010112113 has 4 divisors (see below), whose sum is σ = 11668582985280. Its totient is φ = 8751437238948.

The previous prime is 10210010112053. The next prime is 10210010112161. The reversal of 10210010112113 is 31121101001201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10210010112113 - 2¹⁰ = 10210010111089 is a prime.

It is a super-3 number, since 3×10210010112113³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10210010112163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 729286436573 + ... + 729286436586.

It is an arithmetic number, because the mean of its divisors is an integer number (2917145746320).

Almost surely, 2^{10210010112113} is an apocalyptic number.

It is an amenable number.

10210010112113 is a deficient number, since it is larger than the sum of its proper divisors (1458572873167).

10210010112113 is an equidigital number, since it uses as much as digits as its factorization.

10210010112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1458572873166.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 10210010112113 its reverse (31121101001201), we get a palindrome (41331111113314).

The spelling of 10210010112113 in words is "ten trillion, two hundred ten billion, ten million, one hundred twelve thousand, one hundred thirteen".