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102110016113 = 719375581063
BaseRepresentation
bin101111100011000111…
…0110011001001110001
3100202120020000021012122
41133012032303021301
53133110131003423
6114524140004025
710243244546660
oct1370616631161
9322506007178
10102110016113
113a339495476
1217958530615
1398239c65a1
144d29396dd7
1529c95ce8c8
hex17c63b3271

102110016113 has 8 divisors (see below), whose sum is σ = 117301811328. Its totient is φ = 87069383424.

The previous prime is 102110016103. The next prime is 102110016139. The reversal of 102110016113 is 311610011201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 102110016113 - 210 = 102110015089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102110016091 and 102110016100.

It is not an unprimeable number, because it can be changed into a prime (102110016103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37789181 + ... + 37791882.

It is an arithmetic number, because the mean of its divisors is an integer number (14662726416).

Almost surely, 2102110016113 is an apocalyptic number.

It is an amenable number.

102110016113 is a deficient number, since it is larger than the sum of its proper divisors (15191795215).

102110016113 is an equidigital number, since it uses as much as digits as its factorization.

102110016113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75581263.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 102110016113 its reverse (311610011201), we get a palindrome (413720027314).

The spelling of 102110016113 in words is "one hundred two billion, one hundred ten million, sixteen thousand, one hundred thirteen".

Divisors: 1 7 193 1351 75581063 529067441 14587145159 102110016113