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1021111210113 = 3340370403371
BaseRepresentation
bin11101101101111101111…
…10001001000010000001
310121121122222220000102220
432312332332021002001
5113212213432210423
62101031513001253
7133526042035401
oct16667676110201
93547588800386
101021111210113
11364061726585
12145a940b3229
13753a0c4a747
14375ca148801
151b864d2e9e3
hexedbef89081

1021111210113 has 4 divisors (see below), whose sum is σ = 1361481613488. Its totient is φ = 680740806740.

The previous prime is 1021111210109. The next prime is 1021111210121. The reversal of 1021111210113 is 3110121111201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1021111210113 - 22 = 1021111210109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1021111210092 and 1021111210101.

It is not an unprimeable number, because it can be changed into a prime (1021111210913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170185201683 + ... + 170185201688.

It is an arithmetic number, because the mean of its divisors is an integer number (340370403372).

Almost surely, 21021111210113 is an apocalyptic number.

It is an amenable number.

1021111210113 is a deficient number, since it is larger than the sum of its proper divisors (340370403375).

1021111210113 is an equidigital number, since it uses as much as digits as its factorization.

1021111210113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 340370403374.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 1021111210113 its reverse (3110121111201), we get a palindrome (4131232321314).

The spelling of 1021111210113 in words is "one trillion, twenty-one billion, one hundred eleven million, two hundred ten thousand, one hundred thirteen".

Divisors: 1 3 340370403371 1021111210113