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102112431313 = 671524066139
BaseRepresentation
bin101111100011001100…
…0000000110011010001
3100202120101112222020111
41133012120000303101
53133111240300223
6114524303441321
710243304226244
oct1370630006321
9322511488214
10102112431313
113a33a895002
12179592b6241
1398243609b9
144d2982525b
1529c990a30d
hex17c6600cd1

102112431313 has 4 divisors (see below), whose sum is σ = 103636497520. Its totient is φ = 100588365108.

The previous prime is 102112431301. The next prime is 102112431347. The reversal of 102112431313 is 313134211201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 102112431313 - 233 = 93522496721 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102112431383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 762033003 + ... + 762033136.

It is an arithmetic number, because the mean of its divisors is an integer number (25909124380).

Almost surely, 2102112431313 is an apocalyptic number.

It is an amenable number.

102112431313 is a deficient number, since it is larger than the sum of its proper divisors (1524066207).

102112431313 is an equidigital number, since it uses as much as digits as its factorization.

102112431313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1524066206.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 102112431313 its reverse (313134211201), we get a palindrome (415246642514).

The spelling of 102112431313 in words is "one hundred two billion, one hundred twelve million, four hundred thirty-one thousand, three hundred thirteen".

Divisors: 1 67 1524066139 102112431313