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1021125443035 = 5204225088607
BaseRepresentation
bin11101101101111111101…
…00011011110111011011
310121121200222200010100011
432312333310123313123
5113212231103134120
62101033142022351
7133526304024655
oct16667764336733
93547628603304
101021125443035
11364069767a25
12145a98a179b7
13753a3b91ba9
14375cbdb16d5
151b8661e1c5a
hexedbfd1bddb

1021125443035 has 4 divisors (see below), whose sum is σ = 1225350531648. Its totient is φ = 816900354424.

The previous prime is 1021125442919. The next prime is 1021125443047. The reversal of 1021125443035 is 5303445211201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1021125443035 - 215 = 1021125410267 is a prime.

It is a super-2 number, since 2×10211254430352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1021125442988 and 1021125443006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102112544299 + ... + 102112544308.

It is an arithmetic number, because the mean of its divisors is an integer number (306337632912).

Almost surely, 21021125443035 is an apocalyptic number.

1021125443035 is a deficient number, since it is larger than the sum of its proper divisors (204225088613).

1021125443035 is an equidigital number, since it uses as much as digits as its factorization.

1021125443035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204225088612.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 1021125443035 in words is "one trillion, twenty-one billion, one hundred twenty-five million, four hundred forty-three thousand, thirty-five".

Divisors: 1 5 204225088607 1021125443035