Base | Representation |
---|---|
bin | 1001010010011011111100… |
… | …1001010001100100101001 |
3 | 1100011021211211012022220201 |
4 | 2110212333021101210221 |
5 | 2314304340100021441 |
6 | 33415253000552201 |
7 | 2102550256643662 |
oct | 224467711214451 |
9 | 40137754168821 |
10 | 10212344142121 |
11 | 328803803a970 |
12 | 118b279482661 |
13 | 5910349c3cb4 |
14 | 2743cc812369 |
15 | 12a9a6e65c31 |
hex | 949bf251929 |
10212344142121 has 4 divisors (see below), whose sum is σ = 11140739064144. Its totient is φ = 9283949220100.
The previous prime is 10212344142113. The next prime is 10212344142131. The reversal of 10212344142121 is 12124144321201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10212344142121 - 23 = 10212344142113 is a prime.
It is a super-2 number, since 2×102123441421212 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10212344142121.
It is not an unprimeable number, because it can be changed into a prime (10212344142131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 464197460995 + ... + 464197461016.
It is an arithmetic number, because the mean of its divisors is an integer number (2785184766036).
Almost surely, 210212344142121 is an apocalyptic number.
10212344142121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
10212344142121 is a deficient number, since it is larger than the sum of its proper divisors (928394922023).
10212344142121 is an equidigital number, since it uses as much as digits as its factorization.
10212344142121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 928394922022.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 10212344142121 its reverse (12124144321201), we get a palindrome (22336488463322).
It can be divided in two parts, 102123 and 44142121, that added together give a palindrome (44244244).
The spelling of 10212344142121 in words is "ten trillion, two hundred twelve billion, three hundred forty-four million, one hundred forty-two thousand, one hundred twenty-one".
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