10212421433 has 4 divisors (see below), whose sum is σ = 10216133748. Its totient is φ = 10208709120.

The previous prime is 10212421423. The next prime is 10212421487. The reversal of 10212421433 is 33412421201.

10212421433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33412421201 = 7949 ⋅4203349.

It can be written as a sum of positive squares in 2 ways, for example, as 5552038144 + 4660383289 = 74512^2 + 68267^2 .

It is a cyclic number.

It is not a de Polignac number, because 10212421433 - 2¹² = 10212417337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10212421399 and 10212421408.

It is not an unprimeable number, because it can be changed into a prime (10212421423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1852028 + ... + 1857533.

It is an arithmetic number, because the mean of its divisors is an integer number (2554033437).

Almost surely, 2^10212421433 is an apocalyptic number.

It is an amenable number.

10212421433 is a deficient number, since it is larger than the sum of its proper divisors (3712315).

10212421433 is an equidigital number, since it uses as much as digits as its factorization.

10212421433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3712314.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10212421433 its reverse (33412421201), we get a palindrome (43624842634).

The spelling of 10212421433 in words is "ten billion, two hundred twelve million, four hundred twenty-one thousand, four hundred thirty-three".