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102124330313 = 115878813699
BaseRepresentation
bin101111100011100010…
…1011001110101001001
3100202121012221111121012
41133013011121311021
53133122312032223
6114525410453305
710243510325225
oct1370705316511
9322535844535
10102124330313
113a346581995
1217961294235
139826968a25
144d2b241785
1529ca9aac78
hex17c7159d49

102124330313 has 4 divisors (see below), whose sum is σ = 102133155600. Its totient is φ = 102115505028.

The previous prime is 102124330309. The next prime is 102124330331. The reversal of 102124330313 is 313033421201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 102124330313 - 22 = 102124330309 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102124330303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4395263 + ... + 4418436.

It is an arithmetic number, because the mean of its divisors is an integer number (25533288900).

Almost surely, 2102124330313 is an apocalyptic number.

It is an amenable number.

102124330313 is a deficient number, since it is larger than the sum of its proper divisors (8825287).

102124330313 is an equidigital number, since it uses as much as digits as its factorization.

102124330313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8825286.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 102124330313 its reverse (313033421201), we get a palindrome (415157751514).

The spelling of 102124330313 in words is "one hundred two billion, one hundred twenty-four million, three hundred thirty thousand, three hundred thirteen".

Divisors: 1 11587 8813699 102124330313