10212433113 has 16 divisors (see below), whose sum is σ = 14232620160. Its totient is φ = 6501268224.

The previous prime is 10212433111. The next prime is 10212433141. The reversal of 10212433113 is 31133421201.

10212433113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10212433113 - 2¹ = 10212433111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10212433113.

It is not an unprimeable number, because it can be changed into a prime (10212433111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83878 + ... + 165711.

It is an arithmetic number, because the mean of its divisors is an integer number (889538760).

Almost surely, 2^10212433113 is an apocalyptic number.

It is an amenable number.

10212433113 is a deficient number, since it is larger than the sum of its proper divisors (4020187047).

10212433113 is a wasteful number, since it uses less digits than its factorization.

10212433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 250208.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10212433113 its reverse (31133421201), we get a palindrome (41345854314).

The spelling of 10212433113 in words is "ten billion, two hundred twelve million, four hundred thirty-three thousand, one hundred thirteen".