102131113 has 4 divisors (see below), whose sum is σ = 116721280. Its totient is φ = 87540948.

The previous prime is 102131111. The next prime is 102131119. The reversal of 102131113 is 311131201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311131201 = 6317 ⋅49253.

It is a cyclic number.

It is not a de Polignac number, because 102131113 - 2¹ = 102131111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102131093 and 102131102.

It is not an unprimeable number, because it can be changed into a prime (102131111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7295073 + ... + 7295086.

It is an arithmetic number, because the mean of its divisors is an integer number (29180320).

Almost surely, 2^102131113 is an apocalyptic number.

It is an amenable number.

102131113 is a deficient number, since it is larger than the sum of its proper divisors (14590167).

102131113 is an equidigital number, since it uses as much as digits as its factorization.

102131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14590166.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 102131113 is about 10105.9939145044. The cubic root of 102131113 is about 467.4329841883.

Adding to 102131113 its reverse (311131201), we get a palindrome (413262314).

The spelling of 102131113 in words is "one hundred two million, one hundred thirty-one thousand, one hundred thirteen".