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1021314312505 = 5448883455047
BaseRepresentation
bin11101101110010110001…
…00111010100100111001
310121122012011001200112201
432313023010322210321
5113213122431000010
62101104010110201
7133534056263554
oct16671304724471
93548164050481
101021314312505
113641563383a3
12145b3011b361
137540404cb86
14376090d769b
151b877a9d23a
hexedcb13a939

1021314312505 has 8 divisors (see below), whose sum is σ = 1225582598592. Its totient is φ = 817047834288.

The previous prime is 1021314312497. The next prime is 1021314312509. The reversal of 1021314312505 is 5052134131201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1021314312505 - 23 = 1021314312497 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1021314312509) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2016892 + ... + 2471938.

It is an arithmetic number, because the mean of its divisors is an integer number (153197824824).

Almost surely, 21021314312505 is an apocalyptic number.

It is an amenable number.

1021314312505 is a deficient number, since it is larger than the sum of its proper divisors (204268286087).

1021314312505 is an equidigital number, since it uses as much as digits as its factorization.

1021314312505 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 903935.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 1021314312505 its reverse (5052134131201), we get a palindrome (6073448443706).

The spelling of 1021314312505 in words is "one trillion, twenty-one billion, three hundred fourteen million, three hundred twelve thousand, five hundred five".

Divisors: 1 5 448883 455047 2244415 2275235 204262862501 1021314312505