102132113113 has 4 divisors (see below), whose sum is σ = 102132922320. Its totient is φ = 102131303908.

The previous prime is 102132113093. The next prime is 102132113119. The reversal of 102132113113 is 311311231201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 102132113113 - 2²⁹ = 101595242201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102132113119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169903 + ... + 482836.

It is an arithmetic number, because the mean of its divisors is an integer number (25533230580).

Almost surely, 2^102132113113 is an apocalyptic number.

It is an amenable number.

102132113113 is a deficient number, since it is larger than the sum of its proper divisors (809207).

102132113113 is an equidigital number, since it uses as much as digits as its factorization.

102132113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 809206.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 102132113113 its reverse (311311231201), we get a palindrome (413443344314).

The spelling of 102132113113 in words is "one hundred two billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred thirteen".