Base | Representation |
---|---|
bin | 10011000001100000… |
… | …10011110100101001 |
3 | 222100202221220020010 |
4 | 21200300103310221 |
5 | 131404040231213 |
6 | 4405240322133 |
7 | 511043602425 |
oct | 114060236451 |
9 | 28322856203 |
10 | 10213211433 |
11 | 4371100a07 |
12 | 1b90473349 |
13 | c69c1bc99 |
14 | 6cc5c3b85 |
15 | 3eb976ac3 |
hex | 260c13d29 |
10213211433 has 16 divisors (see below), whose sum is σ = 14233153536. Its totient is φ = 6502016400.
The previous prime is 10213211381. The next prime is 10213211507. The reversal of 10213211433 is 33411231201.
It is not a de Polignac number, because 10213211433 - 212 = 10213207337 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (10213210433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80043 + ... + 163808.
It is an arithmetic number, because the mean of its divisors is an integer number (889572096).
Almost surely, 210213211433 is an apocalyptic number.
It is an amenable number.
10213211433 is a deficient number, since it is larger than the sum of its proper divisors (4019942103).
10213211433 is a wasteful number, since it uses less digits than its factorization.
10213211433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244484.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 10213211433 its reverse (33411231201), we get a palindrome (43624442634).
The spelling of 10213211433 in words is "ten billion, two hundred thirteen million, two hundred eleven thousand, four hundred thirty-three".
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