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1021400115553 = 3191320087783
BaseRepresentation
bin11101101110100000011…
…00001110100101100001
310121122102010111221012101
432313100030032211201
5113213311412144203
62101120313130401
7133536150506326
oct16672014164541
93548363457171
101021400115553
1136419a812504
12145b549b9a01
1375418a626cc
1437616670b4d
151b88039b41d
hexedd030e961

1021400115553 has 4 divisors (see below), whose sum is σ = 1021720206528. Its totient is φ = 1021080024580.

The previous prime is 1021400115551. The next prime is 1021400115601. The reversal of 1021400115553 is 3555110041201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1021400115553 - 21 = 1021400115551 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1021400115551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160040701 + ... + 160047082.

It is an arithmetic number, because the mean of its divisors is an integer number (255430051632).

Almost surely, 21021400115553 is an apocalyptic number.

It is an amenable number.

1021400115553 is a deficient number, since it is larger than the sum of its proper divisors (320090975).

1021400115553 is an equidigital number, since it uses as much as digits as its factorization.

1021400115553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320090974.

The product of its (nonzero) digits is 3000, while the sum is 28.

Adding to 1021400115553 its reverse (3555110041201), we get a palindrome (4576510156754).

The spelling of 1021400115553 in words is "one trillion, twenty-one billion, four hundred million, one hundred fifteen thousand, five hundred fifty-three".

Divisors: 1 3191 320087783 1021400115553