Base | Representation |
---|---|
bin | 11101101110100000011… |
… | …00010011010111010001 |
3 | 10121122102010112221001010 |
4 | 32313100030103113101 |
5 | 113213311413310441 |
6 | 2101120313401133 |
7 | 133536150620352 |
oct | 16672014232721 |
9 | 3548363487033 |
10 | 1021400135121 |
11 | 36419a826183 |
12 | 145b54a091a9 |
13 | 75418a6b5a2 |
14 | 37616677d29 |
15 | 1b8803a2116 |
hex | edd03135d1 |
1021400135121 has 8 divisors (see below), whose sum is σ = 1421078448960. Its totient is φ = 651327622352.
The previous prime is 1021400135117. The next prime is 1021400135149. The reversal of 1021400135121 is 1215310041201.
1021400135121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1021400135121 - 22 = 1021400135117 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1021400135191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7401450186 + ... + 7401450323.
It is an arithmetic number, because the mean of its divisors is an integer number (177634806120).
Almost surely, 21021400135121 is an apocalyptic number.
It is an amenable number.
1021400135121 is a deficient number, since it is larger than the sum of its proper divisors (399678313839).
1021400135121 is a wasteful number, since it uses less digits than its factorization.
1021400135121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14802900535.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 1021400135121 its reverse (1215310041201), we get a palindrome (2236710176322).
The spelling of 1021400135121 in words is "one trillion, twenty-one billion, four hundred million, one hundred thirty-five thousand, one hundred twenty-one".
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