102141351433 has 4 divisors (see below), whose sum is σ = 111426928848. Its totient is φ = 92855774020.

The previous prime is 102141351401. The next prime is 102141351437. The reversal of 102141351433 is 334153141201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334153141201 = 11 ⋅30377558291.

It is a cyclic number.

It is not a de Polignac number, because 102141351433 - 2⁵ = 102141351401 is a prime.

It is a super-2 number, since 2×102141351433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102141351437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4642788691 + ... + 4642788712.

It is an arithmetic number, because the mean of its divisors is an integer number (27856732212).

Almost surely, 2^102141351433 is an apocalyptic number.

It is an amenable number.

102141351433 is a deficient number, since it is larger than the sum of its proper divisors (9285577415).

102141351433 is an equidigital number, since it uses as much as digits as its factorization.

102141351433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9285577414.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 102141351433 its reverse (334153141201), we get a palindrome (436294492634).

The spelling of 102141351433 in words is "one hundred two billion, one hundred forty-one million, three hundred fifty-one thousand, four hundred thirty-three".