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102143130403 = 312371326993
BaseRepresentation
bin101111100100000110…
…1000111101100100011
3100202122112022122110211
41133020031013230203
53133142120133103
6114531321434551
710244126166046
oct1371015075443
9322575278424
10102143130403
113a356152756
121796763ba57
13982a81bc42
144d2d936c5d
1529cc47136d
hex17c8347b23

102143130403 has 4 divisors (see below), whose sum is σ = 102143769768. Its totient is φ = 102142491040.

The previous prime is 102143130379. The next prime is 102143130407. The reversal of 102143130403 is 304031341201.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 102143130403 - 217 = 102142999331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102143130407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148875 + ... + 475867.

It is an arithmetic number, because the mean of its divisors is an integer number (25535942442).

Almost surely, 2102143130403 is an apocalyptic number.

102143130403 is a deficient number, since it is larger than the sum of its proper divisors (639365).

102143130403 is an equidigital number, since it uses as much as digits as its factorization.

102143130403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 639364.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 102143130403 its reverse (304031341201), we get a palindrome (406174471604).

The spelling of 102143130403 in words is "one hundred two billion, one hundred forty-three million, one hundred thirty thousand, four hundred three".

Divisors: 1 312371 326993 102143130403