10214441112113 has 4 divisors (see below), whose sum is σ = 11673646985280. Its totient is φ = 8755235238948.

The previous prime is 10214441112103. The next prime is 10214441112133. The reversal of 10214441112113 is 31121114441201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10214441112113 - 2¹⁰ = 10214441111089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10214441112103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 729602936573 + ... + 729602936586.

It is an arithmetic number, because the mean of its divisors is an integer number (2918411746320).

Almost surely, 2^{10214441112113} is an apocalyptic number.

It is an amenable number.

10214441112113 is a deficient number, since it is larger than the sum of its proper divisors (1459205873167).

10214441112113 is an equidigital number, since it uses as much as digits as its factorization.

10214441112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1459205873166.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 10214441112113 its reverse (31121114441201), we get a palindrome (41335555553314).

The spelling of 10214441112113 in words is "ten trillion, two hundred fourteen billion, four hundred forty-one million, one hundred twelve thousand, one hundred thirteen".