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102204113054451 = 334068037684817
BaseRepresentation
bin10111001111010000111111…
…110110100110101011110011
3111101212121200100212212202020
4113033100333312212223303
5101344003010420220301
61001211531002522523
730346001125033602
oct2717207766465363
9441777610785666
10102204113054451
112a6245803aa911
12b567a12806443
134504a63b825c5
141b349c3b25a39
15bc386bd79436
hex5cf43fda6af3

102204113054451 has 4 divisors (see below), whose sum is σ = 136272150739272. Its totient is φ = 68136075369632.

The previous prime is 102204113054431. The next prime is 102204113054497. The reversal of 102204113054451 is 154450311402201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 102204113054451 - 25 = 102204113054419 is a prime.

It is a super-2 number, since 2×1022041130544512 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (102204113054431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17034018842406 + ... + 17034018842411.

It is an arithmetic number, because the mean of its divisors is an integer number (34068037684818).

Almost surely, 2102204113054451 is an apocalyptic number.

102204113054451 is a deficient number, since it is larger than the sum of its proper divisors (34068037684821).

102204113054451 is an equidigital number, since it uses as much as digits as its factorization.

102204113054451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34068037684820.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 102204113054451 its reverse (154450311402201), we get a palindrome (256654424456652).

The spelling of 102204113054451 in words is "one hundred two trillion, two hundred four billion, one hundred thirteen million, fifty-four thousand, four hundred fifty-one".

Divisors: 1 3 34068037684817 102204113054451