10230024113 has 4 divisors (see below), whose sum is σ = 10236707568. Its totient is φ = 10223340660.

The previous prime is 10230024107. The next prime is 10230024127. The reversal of 10230024113 is 31142003201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31142003201 = 397 ⋅78443333.

It is a cyclic number.

It is not a de Polignac number, because 10230024113 - 2¹⁴ = 10230007729 is a prime.

It is a super-2 number, since 2×10230024113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10230024091 and 10230024100.

It is not an unprimeable number, because it can be changed into a prime (10230024173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3339431 + ... + 3342492.

It is an arithmetic number, because the mean of its divisors is an integer number (2559176892).

Almost surely, 2^10230024113 is an apocalyptic number.

It is an amenable number.

10230024113 is a deficient number, since it is larger than the sum of its proper divisors (6683455).

10230024113 is an equidigital number, since it uses as much as digits as its factorization.

10230024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6683454.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10230024113 its reverse (31142003201), we get a palindrome (41372027314).

The spelling of 10230024113 in words is "ten billion, two hundred thirty million, twenty-four thousand, one hundred thirteen".