10231113113 has 8 divisors (see below), whose sum is σ = 11067533568. Its totient is φ = 9401751504.

The previous prime is 10231113097. The next prime is 10231113143. The reversal of 10231113113 is 31131113201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10231113113 - 2⁴ = 10231113097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10231113091 and 10231113100.

It is not an unprimeable number, because it can be changed into a prime (10231113143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1761695 + ... + 1767492.

It is an arithmetic number, because the mean of its divisors is an integer number (1383441696).

Almost surely, 2^10231113113 is an apocalyptic number.

10231113113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10231113113 is a deficient number, since it is larger than the sum of its proper divisors (836420455).

10231113113 is a wasteful number, since it uses less digits than its factorization.

10231113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3529423.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10231113113 its reverse (31131113201), we get a palindrome (41362226314).

The spelling of 10231113113 in words is "ten billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred thirteen".