1023113000001 has 4 divisors (see below), whose sum is σ = 1364150666672. Its totient is φ = 682075333332.

The previous prime is 1023112999957. The next prime is 1023113000071. The reversal of 1023113000001 is 1000003113201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1023113000001 - 2¹³ = 1023112991809 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1023113000071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170518833331 + ... + 170518833336.

It is an arithmetic number, because the mean of its divisors is an integer number (341037666668).

Almost surely, 2^{1023113000001} is an apocalyptic number.

It is an amenable number.

1023113000001 is a deficient number, since it is larger than the sum of its proper divisors (341037666671).

1023113000001 is an equidigital number, since it uses as much as digits as its factorization.

1023113000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 341037666670.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 1023113000001 its reverse (1000003113201), we get a palindrome (2023116113202).

The spelling of 1023113000001 in words is "one trillion, twenty-three billion, one hundred thirteen million, one", and thus it is an aban number.