Base | Representation |
---|---|
bin | 101111101001000111… |
… | …0101000110000010001 |
3 | 100210002020202112221121 |
4 | 1133102032220300101 |
5 | 3134013143100423 |
6 | 115000130122241 |
7 | 10251240462541 |
oct | 1372216506021 |
9 | 323066675847 |
10 | 102311300113 |
11 | 3a432075090 |
12 | 179b3a20381 |
13 | 9856610149 |
14 | 4d47dd1321 |
15 | 29dc0de45d |
hex | 17d23a8c11 |
102311300113 has 8 divisors (see below), whose sum is σ = 111631453920. Its totient is φ = 92994334080.
The previous prime is 102311300051. The next prime is 102311300137. The reversal of 102311300113 is 311003113201.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 102311300113 - 217 = 102311169041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (102311300153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 729583 + ... + 858436.
It is an arithmetic number, because the mean of its divisors is an integer number (13953931740).
Almost surely, 2102311300113 is an apocalyptic number.
It is an amenable number.
102311300113 is a deficient number, since it is larger than the sum of its proper divisors (9320153807).
102311300113 is a wasteful number, since it uses less digits than its factorization.
102311300113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1593887.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 102311300113 its reverse (311003113201), we get a palindrome (413314413314).
The spelling of 102311300113 in words is "one hundred two billion, three hundred eleven million, three hundred thousand, one hundred thirteen".
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