Search a number
-
+
102311300113 = 1158571588019
BaseRepresentation
bin101111101001000111…
…0101000110000010001
3100210002020202112221121
41133102032220300101
53134013143100423
6115000130122241
710251240462541
oct1372216506021
9323066675847
10102311300113
113a432075090
12179b3a20381
139856610149
144d47dd1321
1529dc0de45d
hex17d23a8c11

102311300113 has 8 divisors (see below), whose sum is σ = 111631453920. Its totient is φ = 92994334080.

The previous prime is 102311300051. The next prime is 102311300137. The reversal of 102311300113 is 311003113201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 102311300113 - 217 = 102311169041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102311300153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 729583 + ... + 858436.

It is an arithmetic number, because the mean of its divisors is an integer number (13953931740).

Almost surely, 2102311300113 is an apocalyptic number.

It is an amenable number.

102311300113 is a deficient number, since it is larger than the sum of its proper divisors (9320153807).

102311300113 is a wasteful number, since it uses less digits than its factorization.

102311300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1593887.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 102311300113 its reverse (311003113201), we get a palindrome (413314413314).

The spelling of 102311300113 in words is "one hundred two billion, three hundred eleven million, three hundred thousand, one hundred thirteen".

Divisors: 1 11 5857 64427 1588019 17468209 9301027283 102311300113