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10233113 = 11930283
BaseRepresentation
bin100111000010…
…010100011001
3201020220012012
4213002110121
510104424423
61003155305
7152660102
oct47022431
921226165
1010233113
11585a320
123515b35
1321739c7
1415053a9
15d72078
hex9c2519

10233113 has 4 divisors (see below), whose sum is σ = 11163408. Its totient is φ = 9302820.

The previous prime is 10233109. The next prime is 10233121. The reversal of 10233113 is 31133201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133201 = 112830291.

It is a cyclic number.

It is not a de Polignac number, because 10233113 - 22 = 10233109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10233173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465131 + ... + 465152.

It is an arithmetic number, because the mean of its divisors is an integer number (2790852).

Almost surely, 210233113 is an apocalyptic number.

It is an amenable number.

10233113 is a deficient number, since it is larger than the sum of its proper divisors (930295).

10233113 is an equidigital number, since it uses as much as digits as its factorization.

10233113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 930294.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 10233113 is about 3198.9237252551. The cubic root of 10233113 is about 217.1047156123.

Adding to 10233113 its reverse (31133201), we get a palindrome (41366314).

The spelling of 10233113 in words is "ten million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 11 930283 10233113