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10233153142307 = 102111002169537
BaseRepresentation
bin1001010011101001011101…
…1101010011111000100011
31100020021120001000001210022
42110322113131103320203
52320124444201023212
633433013510024055
72104215034351004
oct224722735237043
940207501001708
1010233153142307
113295946197787
12119330634802b
13592c9cb83264
142754043271ab
1512b2c3c35772
hex94e97753e23

10233153142307 has 4 divisors (see below), whose sum is σ = 10234155322056. Its totient is φ = 10232150962560.

The previous prime is 10233153142301. The next prime is 10233153142321. The reversal of 10233153142307 is 70324135133201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10233153142307 - 236 = 10164433665571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10233153142301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501074558 + ... + 501094979.

It is an arithmetic number, because the mean of its divisors is an integer number (2558538830514).

Almost surely, 210233153142307 is an apocalyptic number.

10233153142307 is a deficient number, since it is larger than the sum of its proper divisors (1002179749).

10233153142307 is a wasteful number, since it uses less digits than its factorization.

10233153142307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1002179748.

The product of its (nonzero) digits is 45360, while the sum is 35.

Adding to 10233153142307 its reverse (70324135133201), we get a palindrome (80557288275508).

The spelling of 10233153142307 in words is "ten trillion, two hundred thirty-three billion, one hundred fifty-three million, one hundred forty-two thousand, three hundred seven".

Divisors: 1 10211 1002169537 10233153142307