102333113 has 4 divisors (see below), whose sum is σ = 102476160. Its totient is φ = 102190068.

The previous prime is 102333103. The next prime is 102333151. The reversal of 102333113 is 311333201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 102333113 - 2²² = 98138809 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 102333091 and 102333100.

It is not an unprimeable number, because it can be changed into a prime (102333103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70445 + ... + 71882.

It is an arithmetic number, because the mean of its divisors is an integer number (25619040).

Almost surely, 2^102333113 is an apocalyptic number.

It is an amenable number.

102333113 is a deficient number, since it is larger than the sum of its proper divisors (143047).

102333113 is an equidigital number, since it uses as much as digits as its factorization.

102333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 143046.

The product of its (nonzero) digits is 162, while the sum is 17.

The square root of 102333113 is about 10115.9830466446. The cubic root of 102333113 is about 467.7409519820.

Adding to 102333113 its reverse (311333201), we get a palindrome (413666314).

The spelling of 102333113 in words is "one hundred two million, three hundred thirty-three thousand, one hundred thirteen".