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10241115210433 = 192657202862651
BaseRepresentation
bin1001010100000111001000…
…0010001100001011000001
31100021001002221001000221101
42111001302002030023001
52320242300443213213
633440411532454401
72104616244665422
oct225016202141301
940231087030841
1010241115210433
113299261607378
12119496891a401
1359396b5a4c83
1427595b959649
1512b5dcc3bbdd
hex9507208c2c1

10241115210433 has 8 divisors (see below), whose sum is σ = 10784178580320. Its totient is φ = 9698457571200.

The previous prime is 10241115210397. The next prime is 10241115210437. The reversal of 10241115210433 is 33401251114201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10241115210433 - 29 = 10241115209921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10241115210437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101380843 + ... + 101481808.

It is an arithmetic number, because the mean of its divisors is an integer number (1348022322540).

Almost surely, 210241115210433 is an apocalyptic number.

It is an amenable number.

10241115210433 is a deficient number, since it is larger than the sum of its proper divisors (543063369887).

10241115210433 is a wasteful number, since it uses less digits than its factorization.

10241115210433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202865327.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 10241115210433 its reverse (33401251114201), we get a palindrome (43642366324634).

The spelling of 10241115210433 in words is "ten trillion, two hundred forty-one billion, one hundred fifteen million, two hundred ten thousand, four hundred thirty-three".

Divisors: 1 19 2657 50483 202862651 3854390369 539006063707 10241115210433