Search a number
-
+
102414444121 = 119310404011
BaseRepresentation
bin101111101100001100…
…0000110011001011001
3100210100102211210221001
41133120120012121121
53134221044202441
6115014252545001
710253632261123
oct1373030063131
9323312753831
10102414444121
113a485313770
1217a22482161
139871ab49c2
144d579a0213
1529e61b5731
hex17d8606659

102414444121 has 4 divisors (see below), whose sum is σ = 111724848144. Its totient is φ = 93104040100.

The previous prime is 102414444109. The next prime is 102414444203. The reversal of 102414444121 is 121444414201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121444414201 = 1111040401291.

It is a cyclic number.

It is not a de Polignac number, because 102414444121 - 29 = 102414443609 is a prime.

It is a super-2 number, since 2×1024144441212 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 102414444121.

It is not an unprimeable number, because it can be changed into a prime (102414444101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4655201995 + ... + 4655202016.

It is an arithmetic number, because the mean of its divisors is an integer number (27931212036).

Almost surely, 2102414444121 is an apocalyptic number.

102414444121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

102414444121 is a deficient number, since it is larger than the sum of its proper divisors (9310404023).

102414444121 is an equidigital number, since it uses as much as digits as its factorization.

102414444121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9310404022.

The product of its (nonzero) digits is 4096, while the sum is 28.

Adding to 102414444121 its reverse (121444414201), we get a palindrome (223858858322).

It can be divided in two parts, 102414 and 444121, that added together give a triangular number (546535 = T1045).

The spelling of 102414444121 in words is "one hundred two billion, four hundred fourteen million, four hundred forty-four thousand, one hundred twenty-one".

Divisors: 1 11 9310404011 102414444121