Base | Representation |
---|---|
bin | 101111101100010110… |
… | …1110101110101001001 |
3 | 100210100211120100220200 |
4 | 1133120231311311021 |
5 | 3134224024042213 |
6 | 115015015042413 |
7 | 10254031566156 |
oct | 1373055656511 |
9 | 323324510820 |
10 | 102420143433 |
11 | 3a488556743 |
12 | 17a24370409 |
13 | 987302bb8a |
14 | 4d5864522d |
15 | 29e693e273 |
hex | 17d8b75d49 |
102420143433 has 12 divisors (see below), whose sum is σ = 147986961408. Its totient is φ = 68258516760.
The previous prime is 102420143333. The next prime is 102420143453. The reversal of 102420143433 is 334341024201.
102420143433 is a `hidden beast` number, since 1 + 0 + 24 + 201 + 4 + 3 + 433 = 666.
It is not a de Polignac number, because 102420143433 - 216 = 102420077897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102420143397 and 102420143406.
It is not an unprimeable number, because it can be changed into a prime (102420143453) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1768153 + ... + 1825158.
It is an arithmetic number, because the mean of its divisors is an integer number (12332246784).
Almost surely, 2102420143433 is an apocalyptic number.
It is an amenable number.
102420143433 is a deficient number, since it is larger than the sum of its proper divisors (45566817975).
102420143433 is a wasteful number, since it uses less digits than its factorization.
102420143433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3596484 (or 3596481 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 102420143433 its reverse (334341024201), we get a palindrome (436761167634).
The spelling of 102420143433 in words is "one hundred two billion, four hundred twenty million, one hundred forty-three thousand, four hundred thirty-three".
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