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102420143433 = 3231673593311
BaseRepresentation
bin101111101100010110…
…1110101110101001001
3100210100211120100220200
41133120231311311021
53134224024042213
6115015015042413
710254031566156
oct1373055656511
9323324510820
10102420143433
113a488556743
1217a24370409
13987302bb8a
144d5864522d
1529e693e273
hex17d8b75d49

102420143433 has 12 divisors (see below), whose sum is σ = 147986961408. Its totient is φ = 68258516760.

The previous prime is 102420143333. The next prime is 102420143453. The reversal of 102420143433 is 334341024201.

102420143433 is a `hidden beast` number, since 1 + 0 + 24 + 201 + 4 + 3 + 433 = 666.

It is not a de Polignac number, because 102420143433 - 216 = 102420077897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102420143397 and 102420143406.

It is not an unprimeable number, because it can be changed into a prime (102420143453) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1768153 + ... + 1825158.

It is an arithmetic number, because the mean of its divisors is an integer number (12332246784).

Almost surely, 2102420143433 is an apocalyptic number.

It is an amenable number.

102420143433 is a deficient number, since it is larger than the sum of its proper divisors (45566817975).

102420143433 is a wasteful number, since it uses less digits than its factorization.

102420143433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3596484 (or 3596481 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 102420143433 its reverse (334341024201), we get a palindrome (436761167634).

The spelling of 102420143433 in words is "one hundred two billion, four hundred twenty million, one hundred forty-three thousand, four hundred thirty-three".

Divisors: 1 3 9 3167 9501 28503 3593311 10779933 32339799 11380015937 34140047811 102420143433