Base | Representation |
---|---|
bin | 1001010100001111000111… |
… | …1000011011001011100001 |
3 | 1100021020122102002110002011 |
4 | 2111003301320123023201 |
5 | 2320311144043242423 |
6 | 33441404433552521 |
7 | 2105023351355266 |
oct | 225036170331341 |
9 | 40236572073064 |
10 | 10243260134113 |
11 | 329a162339276 |
12 | 1195267115741 |
13 | 593c20a91796 |
14 | 275ac277b26d |
15 | 12b6b61c9b0d |
hex | 950f1e1b2e1 |
10243260134113 has 8 divisors (see below), whose sum is σ = 10786225872800. Its totient is φ = 9700679073888.
The previous prime is 10243260134101. The next prime is 10243260134131. The reversal of 10243260134113 is 31143106234201.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10243260134113 - 213 = 10243260125921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10243264134113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 96114948 + ... + 96221461.
It is an arithmetic number, because the mean of its divisors is an integer number (1348278234100).
Almost surely, 210243260134113 is an apocalyptic number.
It is an amenable number.
10243260134113 is a deficient number, since it is larger than the sum of its proper divisors (542965738687).
10243260134113 is a wasteful number, since it uses less digits than its factorization.
10243260134113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 192339231.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 10243260134113 its reverse (31143106234201), we get a palindrome (41386366368314).
The spelling of 10243260134113 in words is "ten trillion, two hundred forty-three billion, two hundred sixty million, one hundred thirty-four thousand, one hundred thirteen".
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