1024443134041 has 4 divisors (see below), whose sum is σ = 1057489686784. Its totient is φ = 991396581300.

The previous prime is 1024443133993. The next prime is 1024443134081. The reversal of 1024443134041 is 1404313444201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1024443134041 - 2¹⁵ = 1024443101273 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 33046552711 = 1024443134041 / (1 + 0 + 2 + 4 + 4 + 4 + 3 + 1 + 3 + 4 + 0 + 4 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1024443133994 and 1024443134012.

It is not an unprimeable number, because it can be changed into a prime (1024443134081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16523276325 + ... + 16523276386.

It is an arithmetic number, because the mean of its divisors is an integer number (264372421696).

Almost surely, 2^{1024443134041} is an apocalyptic number.

It is an amenable number.

1024443134041 is a deficient number, since it is larger than the sum of its proper divisors (33046552743).

1024443134041 is an equidigital number, since it uses as much as digits as its factorization.

1024443134041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33046552742.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1024443134041 its reverse (1404313444201), we get a palindrome (2428756578242).

The spelling of 1024443134041 in words is "one trillion, twenty-four billion, four hundred forty-three million, one hundred thirty-four thousand, forty-one".