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10252143011 = 11932013001
BaseRepresentation
bin10011000110001001…
…10100100110100011
3222110111012211022102
421203010310212203
5131444022034021
64413151001015
7512025530525
oct114304644643
928414184272
1010252143011
114391081870
121ba150916b
13c75000416
146d3839a15
154000b700b
hex2631349a3

10252143011 has 4 divisors (see below), whose sum is σ = 11184156024. Its totient is φ = 9320130000.

The previous prime is 10252143001. The next prime is 10252143043. The reversal of 10252143011 is 11034125201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10252143011 - 218 = 10251880867 is a prime.

It is a super-2 number, since 2×102521430112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10252143001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 466006490 + ... + 466006511.

It is an arithmetic number, because the mean of its divisors is an integer number (2796039006).

Almost surely, 210252143011 is an apocalyptic number.

10252143011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10252143011 is a deficient number, since it is larger than the sum of its proper divisors (932013013).

10252143011 is an equidigital number, since it uses as much as digits as its factorization.

10252143011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 932013012.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 10252143011 its reverse (11034125201), we get a palindrome (21286268212).

The spelling of 10252143011 in words is "ten billion, two hundred fifty-two million, one hundred forty-three thousand, eleven".

Divisors: 1 11 932013001 10252143011