10254045221131 has 4 divisors (see below), whose sum is σ = 10256004722872. Its totient is φ = 10252085719392.

The previous prime is 10254045221113. The next prime is 10254045221137. The reversal of 10254045221131 is 13112254045201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10254045221131 - 2¹¹ = 10254045219083 is a prime.

It is a super-2 number, since 2×10254045221131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10254045221093 and 10254045221102.

It is not an unprimeable number, because it can be changed into a prime (10254045221137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 979743021 + ... + 979753486.

It is an arithmetic number, because the mean of its divisors is an integer number (2564001180718).

Almost surely, 2^{10254045221131} is an apocalyptic number.

10254045221131 is a deficient number, since it is larger than the sum of its proper divisors (1959501741).

10254045221131 is an equidigital number, since it uses as much as digits as its factorization.

10254045221131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1959501740.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 10254045221131 its reverse (13112254045201), we get a palindrome (23366299266332).

The spelling of 10254045221131 in words is "ten trillion, two hundred fifty-four billion, forty-five million, two hundred twenty-one thousand, one hundred thirty-one".