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10276113 = 33425371
BaseRepresentation
bin100111001100…
…110100010001
3201100002011210
4213030310101
510112313423
61004130333
7153226341
oct47146421
921302153
1010276113
115889661
1235369a9
13218a453
141516d21
15d7eb93
hex9ccd11

10276113 has 4 divisors (see below), whose sum is σ = 13701488. Its totient is φ = 6850740.

The previous prime is 10276099. The next prime is 10276153. The reversal of 10276113 is 31167201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10276113 - 25 = 10276081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10276113.

It is not an unprimeable number, because it can be changed into a prime (10276153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1712683 + ... + 1712688.

It is an arithmetic number, because the mean of its divisors is an integer number (3425372).

Almost surely, 210276113 is an apocalyptic number.

It is an amenable number.

10276113 is a deficient number, since it is larger than the sum of its proper divisors (3425375).

10276113 is an equidigital number, since it uses as much as digits as its factorization.

10276113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3425374.

The product of its (nonzero) digits is 252, while the sum is 21.

The square root of 10276113 is about 3205.6376900704. The cubic root of 10276113 is about 217.4083852498.

It can be divided in two parts, 1027 and 6113, that added together give a triangular number (7140 = T119).

The spelling of 10276113 in words is "ten million, two hundred seventy-six thousand, one hundred thirteen".

Divisors: 1 3 3425371 10276113