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103000434121 = 1349547159911
BaseRepresentation
bin101111111101101001…
…1011110010111001001
3100211212021111012002101
41133323103132113021
53141421102342441
6115152344433401
710304306146564
oct1377323362711
9324767435071
10103000434121
113a756072722
1217b66778861
139936316750
144db173b4db
152a2c867231
hex17fb4de5c9

103000434121 has 8 divisors (see below), whose sum is σ = 110926476864. Its totient is φ = 95074810320.

The previous prime is 103000434113. The next prime is 103000434133. The reversal of 103000434121 is 121434000301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103000434121 - 23 = 103000434113 is a prime.

It is a super-2 number, since 2×1030004341212 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103000434191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 564156 + ... + 724066.

It is an arithmetic number, because the mean of its divisors is an integer number (13865809608).

Almost surely, 2103000434121 is an apocalyptic number.

It is an amenable number.

103000434121 is a deficient number, since it is larger than the sum of its proper divisors (7926042743).

103000434121 is a wasteful number, since it uses less digits than its factorization.

103000434121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 209471.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 103000434121 its reverse (121434000301), we get a palindrome (224434434422).

The spelling of 103000434121 in words is "one hundred three billion, four hundred thirty-four thousand, one hundred twenty-one".

Divisors: 1 13 49547 159911 644111 2078843 7923110317 103000434121