Base | Representation |
---|---|
bin | 11101111110100010111… |
… | …00010001011000101011 |
3 | 10122110122020110212110122 |
4 | 32333101130101120223 |
5 | 113333430311030011 |
6 | 2105102555033455 |
7 | 134262430216313 |
oct | 16772134213053 |
9 | 3573566425418 |
10 | 1030011033131 |
11 | 367909415313 |
12 | 14775873b88b |
13 | 7618ba24802 |
14 | 37bd2124443 |
15 | 1bbd631e3db |
hex | efd171162b |
1030011033131 has 4 divisors (see below), whose sum is σ = 1074794121552. Its totient is φ = 985227944712.
The previous prime is 1030011033119. The next prime is 1030011033137. The reversal of 1030011033131 is 1313301100301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1030011033131 is a prime.
It is a super-2 number, since 2×10300110331312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1030011033137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22391544176 + ... + 22391544221.
It is an arithmetic number, because the mean of its divisors is an integer number (268698530388).
Almost surely, 21030011033131 is an apocalyptic number.
1030011033131 is a deficient number, since it is larger than the sum of its proper divisors (44783088421).
1030011033131 is an equidigital number, since it uses as much as digits as its factorization.
1030011033131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44783088420.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1030011033131 its reverse (1313301100301), we get a palindrome (2343312133432).
The spelling of 1030011033131 in words is "one trillion, thirty billion, eleven million, thirty-three thousand, one hundred thirty-one".
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