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103003131131 = 412512271491
BaseRepresentation
bin101111111101101110…
…1110000110011111011
3100211212110120012200122
41133323131300303323
53141422300144011
6115152522323455
710304341111565
oct1377335606373
9324773505618
10103003131131
113a757644a5a
1217b6765958b
139936a4c204
144db1c40335
152a2cbeb3db
hex17fb770cfb

103003131131 has 4 divisors (see below), whose sum is σ = 105515402664. Its totient is φ = 100490859600.

The previous prime is 103003131083. The next prime is 103003131139. The reversal of 103003131131 is 131131300301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131131300301 = 947313842637.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103003131131 is a prime.

It is a super-2 number, since 2×1030031311312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103003131139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1256135705 + ... + 1256135786.

It is an arithmetic number, because the mean of its divisors is an integer number (26378850666).

Almost surely, 2103003131131 is an apocalyptic number.

103003131131 is a deficient number, since it is larger than the sum of its proper divisors (2512271533).

103003131131 is an equidigital number, since it uses as much as digits as its factorization.

103003131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2512271532.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 103003131131 its reverse (131131300301), we get a palindrome (234134431432).

The spelling of 103003131131 in words is "one hundred three billion, three million, one hundred thirty-one thousand, one hundred thirty-one".

Divisors: 1 41 2512271491 103003131131