103004113 has 4 divisors (see below), whose sum is σ = 103024548. Its totient is φ = 102983680.

The previous prime is 103004087. The next prime is 103004131. The reversal of 103004113 is 311400301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311400301 = 31 ⋅10045171.

It can be written as a sum of positive squares in 2 ways, for example, as 93566929 + 9437184 = 9673^2 + 3072^2 .

It is a cyclic number.

It is not a de Polignac number, because 103004113 - 2⁹ = 103003601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103004093 and 103004102.

It is not an unprimeable number, because it can be changed into a prime (103004183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3345 + ... + 14737.

It is an arithmetic number, because the mean of its divisors is an integer number (25756137).

Almost surely, 2^103004113 is an apocalyptic number.

It is an amenable number.

103004113 is a deficient number, since it is larger than the sum of its proper divisors (20435).

103004113 is an equidigital number, since it uses as much as digits as its factorization.

103004113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20434.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 103004113 is about 10149.0941960354. The cubic root of 103004113 is about 468.7610541275.

Adding to 103004113 its reverse (311400301), we get a palindrome (414404414).

The spelling of 103004113 in words is "one hundred three million, four thousand, one hundred thirteen".