103011301110113 has 4 divisors (see below), whose sum is σ = 112375964847408. Its totient is φ = 93646637372820.

The previous prime is 103011301110061. The next prime is 103011301110143. The reversal of 103011301110113 is 311011103110301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-103011301110113 is a prime.

It is a super-2 number, since 2×103011301110113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103011301110091 and 103011301110100.

It is not an unprimeable number, because it can be changed into a prime (103011301110143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4682331868631 + ... + 4682331868652.

It is an arithmetic number, because the mean of its divisors is an integer number (28093991211852).

Almost surely, 2^{103011301110113} is an apocalyptic number.

It is an amenable number.

103011301110113 is a deficient number, since it is larger than the sum of its proper divisors (9364663737295).

103011301110113 is an equidigital number, since it uses as much as digits as its factorization.

103011301110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9364663737294.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 103011301110113 its reverse (311011103110301), we get a palindrome (414022404220414).

The spelling of 103011301110113 in words is "one hundred three trillion, eleven billion, three hundred one million, one hundred ten thousand, one hundred thirteen".