Search a number
-
+
103011332011 = 714715904573
BaseRepresentation
bin101111111101111110…
…1000010111110101011
3100211220000222212011221
41133323331002332223
53141431400111021
6115153414202511
710304500606060
oct1377375027653
9324800885157
10103011332011
113a761236445
1217b6a353437
139938660bc3
144db2d76c67
152a2d7bb241
hex17fbf42fab

103011332011 has 4 divisors (see below), whose sum is σ = 117727236592. Its totient is φ = 88295427432.

The previous prime is 103011332009. The next prime is 103011332027. The reversal of 103011332011 is 110233110301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103011332011 - 21 = 103011332009 is a prime.

It is a super-3 number, since 3×1030113320113 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (103011332051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7357952280 + ... + 7357952293.

It is an arithmetic number, because the mean of its divisors is an integer number (29431809148).

Almost surely, 2103011332011 is an apocalyptic number.

103011332011 is a deficient number, since it is larger than the sum of its proper divisors (14715904581).

103011332011 is an equidigital number, since it uses as much as digits as its factorization.

103011332011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14715904580.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 103011332011 its reverse (110233110301), we get a palindrome (213244442312).

The spelling of 103011332011 in words is "one hundred three billion, eleven million, three hundred thirty-two thousand, eleven".

Divisors: 1 7 14715904573 103011332011