10302113 has 4 divisors (see below), whose sum is σ = 10383360. Its totient is φ = 10220868.

The previous prime is 10302077. The next prime is 10302139. The reversal of 10302113 is 31120301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10302113 - 2¹⁰ = 10301089 is a prime.

It is a super-2 number, since 2×10302113² = 212267064529538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10302094 and 10302103.

It is not an unprimeable number, because it can be changed into a prime (10302143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40433 + ... + 40686.

It is an arithmetic number, because the mean of its divisors is an integer number (2595840).

Almost surely, 2^10302113 is an apocalyptic number.

It is an amenable number.

10302113 is a deficient number, since it is larger than the sum of its proper divisors (81247).

10302113 is an equidigital number, since it uses as much as digits as its factorization.

10302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81246.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 10302113 is about 3209.6904835202. The cubic root of 10302113 is about 217.5915886783.

Adding to 10302113 its reverse (31120301), we get a palindrome (41422414).

The spelling of 10302113 in words is "ten million, three hundred two thousand, one hundred thirteen".