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1030212302113 = 8312412196411
BaseRepresentation
bin11101111110111010111…
…00000011010100100001
310122111011021012101121101
432333131130003110201
5113334333322131423
62105134544554401
7134300423040331
oct16773534032441
93574137171541
101030212302113
11367a01a94715
121477b4022a01
13761c1634597
1437c10b570c1
151bbe8d297ad
hexefdd703521

1030212302113 has 4 divisors (see below), whose sum is σ = 1042624498608. Its totient is φ = 1017800105620.

The previous prime is 1030212302107. The next prime is 1030212302177. The reversal of 1030212302113 is 3112032120301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1030212302113 - 217 = 1030212171041 is a prime.

It is a super-2 number, since 2×10302123021132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1030212302183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6206098123 + ... + 6206098288.

It is an arithmetic number, because the mean of its divisors is an integer number (260656124652).

Almost surely, 21030212302113 is an apocalyptic number.

It is an amenable number.

1030212302113 is a deficient number, since it is larger than the sum of its proper divisors (12412196495).

1030212302113 is an equidigital number, since it uses as much as digits as its factorization.

1030212302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12412196494.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1030212302113 its reverse (3112032120301), we get a palindrome (4142244422414).

The spelling of 1030212302113 in words is "one trillion, thirty billion, two hundred twelve million, three hundred two thousand, one hundred thirteen".

Divisors: 1 83 12412196411 1030212302113