1030213001 has 4 divisors (see below), whose sum is σ = 1030399104. Its totient is φ = 1030026900.

The previous prime is 1030212991. The next prime is 1030213007. The reversal of 1030213001 is 1003120301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1003120301 = 59 ⋅17002039.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1030213001 is a prime.

It is a super-2 number, since 2×1030213001² = 2122677654858852002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1030213007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84485 + ... + 95906.

It is an arithmetic number, because the mean of its divisors is an integer number (257599776).

Almost surely, 2^1030213001 is an apocalyptic number.

It is an amenable number.

1030213001 is a deficient number, since it is larger than the sum of its proper divisors (186103).

1030213001 is an equidigital number, since it uses as much as digits as its factorization.

1030213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186102.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1030213001 is about 32096.9313330729. The cubic root of 1030213001 is about 1009.9712441573.

Adding to 1030213001 its reverse (1003120301), we get a palindrome (2033333302).

The spelling of 1030213001 in words is "one billion, thirty million, two hundred thirteen thousand, one".